4.9t^2+t+148=0

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Solution for 4.9t^2+t+148=0 equation: 



4.9t^2+t+148=0

a = 4.9; b = 1; c = +148;
Δ = b2-4ac
Δ = 12-4·4.9·148
Δ = -2899.8
Delta is less than zero, so there is no solution for the equation

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